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Altera_Forum
Honored Contributor
16 years agoneed help of the readmemb function in verilog
Hi,
I wrote a code to read data from a .txt file and output the data to the AD/DA card. But the output of the module is a constant value. (the text file has 8192 binary numbers with different value). Can I get some help? This is really urgent:confused:. Truly appreciate your kindly help. Thanks. Following is my code. module readfile ( clock,data_out); input clock; output [13:0] data_out; parameter size = 8192; //data size reg [13:0] read_mem[1:size]; reg [13:0] data_out; integer a; initial $readmemb ("data.txt", read_mem); always @(posedge clock) begin for (a=1; a<size+1; a=a+1) begin if (clock) // output frequency depends on the frequency of the input clock data_out <= read_mem[a]; end end endmodule Many many thanks.6 Replies
- Altera_Forum
Honored Contributor
Thanks for your kindly help. The code works well.
BTW, I find it also works if I remove the "for" loop, just use readmemb function once. Thanks a lot for your suggestions. Regards, Lyila - Altera_Forum
Honored Contributor
Thank you sooo much. The code works know.
Thanks and regard, Lyila - Altera_Forum
Honored Contributor
--- Quote Start --- Hi, I wrote a code to read data from a .txt file and output the data to the AD/DA card. But the output of the module is a constant value. (the text file has 8192 binary numbers with different value). Can I get some help? This is really urgent:confused:. Truly appreciate your kindly help. Thanks. Following is my code. module readfile ( clock,data_out); input clock; output [13:0] data_out; parameter size = 8192; //data size reg [13:0] read_mem[1:size]; reg [13:0] data_out; integer a; initial $readmemb ("data.txt", read_mem); always @(posedge clock) begin for (a=1; a<size+1; a=a+1) begin if (clock) // output frequency depends on the frequency of the input clock data_out <= read_mem[a]; end end endmodule Many many thanks./QUOTE] Hi, i have written an example for you were you can seee howt could work: module read_file ( clock,data_out); input clock; output [13:0] data_out; parameter size = 10; //data size 8192 reg [13:0] read_mem; reg [13:0] data_out; integer a; // ROM generation // ROM is filled with the data of the text file initial begin for (a=0; a<size; a=a+1) $readmemb ("data.txt", read_mem); end // ROM is read continuously reg [9:0] i; always@(posedge clock) begin data_out<= read_mem[i]; i <= i + 1; end endmodule You always have to keep in mind that your code is converted to hardware. That means for the intial part Quartus generates a ROM, filled with the data of the text file. That means every time when you would like to change the data, you have to run Quartus again. In order to see the data continuously you have to read every clock cycle one address of your ROM. BTW: the default loop limit is 5000. If you need more you have to change the setting in Quartus. One way to do that is: Assignments -> Settings -> Analyse & Synthesis Settings -> more -> look for "Iteration limit for constant Verilog loops. Kind regards GPK - Altera_Forum
Honored Contributor
this code will output data repeatedly.
when i==8191, i=i+1 will result in 0 because i is 13-bit width. - Altera_Forum
Honored Contributor
Thanks for your help, loywong.
I'll test the code to see if I can get the correct output. If I need to output the data repeatedly, how can I change the code? Thanks again. - Altera_Forum
Honored Contributor
there is no problems with your memory initializing if you have a correct format of "data.txt".
but you misunderstood the function of keyword "for", it describes implementing repeation of hardware but not cycle of procedure as in "c" language. I guess you got a constant of the last word in your memory, right? you should wrote: reg [12 : 0] i; always@(posedge clk) begin data_out <= read_mem[i + 1]; i <= i + 1; end