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Mahdi's avatar
Mahdi
Icon for Occasional Contributor rankOccasional Contributor
3 years ago
Solved

Understanding address map in EMIF

Hi,

I am trying to read/write from/to an external memory model during the simulation using EMIF.

I have some questions regarding the address map in EMIF.

Based on this configuration, what should be the address width? I guess it should be 29 bits, right?

But, why the amm_address is 26 bits here?

Also, I can't understand why mem_a is 17 bits.

The other problem is that I don't know how to generate certain addresses if I want to read or write from/to memory. What is the meaning of each bit of this 26-bit amm_address?

Here is the Controller configuration:

Thank,

-- Mahdi

  • AdzimZM_Altera's avatar
    AdzimZM_Altera
    3 years ago

    For the address ordering that you used:

    CS-CID-Row-Bank-Column-BG

    The CS is available only when there is multiple rank.

    The CID is for 3D stacked interface. No CID bit in this configuration.

    Row address width = 15.

    Column address width = 10.***

    Bank address width = 2.

    Bank group width = 2.

    ***(Lower 3 bits has been set to 0 because Avalon bus is 8x wider than EMIF bus in Quarter rate. Therefore it's removed when mapping to Avalon address)

    The ordering will be as below:

    Row[14..0] = amm_address[25..11]

    Bank[1..0] = amm_address[10..9]

    Column[9..3] = amm_address[8..2]

    BG[1..0] = amm_address[1..0]

5 Replies

  • AdzimZM_Altera's avatar
    AdzimZM_Altera
    Icon for Regular Contributor rankRegular Contributor
    3 years ago

    Hi Mahdi,


    Thank you for submitting your question in Intel Community.

    I'm Adzim, application engineer will assist you in this thread.


    In my opinion, you need to refer to memory datasheet for the truth table of the memory commands.


    Cheers,

    Adzim


    • Mahdi's avatar
      Mahdi
      Icon for Occasional Contributor rankOccasional Contributor
      3 years ago

      Hi Adzim,

      Thanks for your reply. I am not using the actual memory system. I am using the memory IP core that is generated in EMIF design example, and I do not know its specifications.

      - Mahdi

  • AdzimZM_Altera's avatar
    AdzimZM_Altera
    Icon for Regular Contributor rankRegular Contributor
    3 years ago

    For the address ordering that you used:

    CS-CID-Row-Bank-Column-BG

    The CS is available only when there is multiple rank.

    The CID is for 3D stacked interface. No CID bit in this configuration.

    Row address width = 15.

    Column address width = 10.***

    Bank address width = 2.

    Bank group width = 2.

    ***(Lower 3 bits has been set to 0 because Avalon bus is 8x wider than EMIF bus in Quarter rate. Therefore it's removed when mapping to Avalon address)

    The ordering will be as below:

    Row[14..0] = amm_address[25..11]

    Bank[1..0] = amm_address[10..9]

    Column[9..3] = amm_address[8..2]

    BG[1..0] = amm_address[1..0]

    • Mahdi's avatar
      Mahdi
      Icon for Occasional Contributor rankOccasional Contributor
      3 years ago

      Oh, I see. I did not know this fact. Thank you so much for your explanation.

      - Mahdi

  • AdzimZM_Altera's avatar
    AdzimZM_Altera
    Icon for Regular Contributor rankRegular Contributor
    3 years ago

    I’m glad that your question has been addressed, I now transition this thread to community support. If you have a new question, feel free to open a new thread to get the support from Intel experts. Otherwise, the community users will continue to help you on this thread. Thank you.