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Yamada1's avatar
Yamada1
Icon for Occasional Contributor rankOccasional Contributor
2 years ago
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About IO PLL

It would be helpful if you could tell me about the Advanced Parameter tab of the IOPLL Intel FPGA IP settings. PLL is in direct mode.

1) Is it correct to understand that C-Counter-0 Divide Setting is the PLL output frequency division ratio for the VCO frequency?

2) If 1) is correct, is it correct that if this is an odd value, the PLL output duty will not be 50%? Or does it mean that if C-Counter-0 Even Duty Enable is true, the duty will be corrected to 50%?

3) If the duty is corrected in 2), will it affect jitter performance?

Sorry for the basic question, but I would appreciate it if you could explain it to me.

5 Replies

  • AqidAyman_Altera's avatar
    AqidAyman_Altera
    Icon for Regular Contributor rankRegular Contributor

    Hello,


    May I know you are referring to what device for this IOPLL IP?


    Regards,

    Aqid


    • Yamada1's avatar
      Yamada1
      Icon for Occasional Contributor rankOccasional Contributor

      Thank you for your response.

      The description was missing. very sorry.

      The device used is 10AX115S2F45I1SG.

      We apologize for the inconvenience, but it would be helpful if you could teach us.

  • AqidAyman_Altera's avatar
    AqidAyman_Altera
    Icon for Regular Contributor rankRegular Contributor

    Thank you for the device part number. Please refer to the answer below:

    1. Yes, you are correct. The output clock frequency is the result of the VCO frequency divided by the counter value. Can refer to Figure 64 in below link https://www.intel.com/content/www/us/en/docs/programmable/683461/current/pll-architecture.html
    2. For this one, I think we used to call it odd division factor, where we use a negative edge clock to normalize the duty cycle to 50/50. Another that, you can take a look on this link https://www.intel.com/content/www/us/en/docs/programmable/683845/current/address-bus-and-data-bus-setting-for-23451.html
    3. I don't think it affect jitter; it simply uses a falling edge instead of rising edge. If it did affect jitter, we would have to produce a different jitter spec for when that even duty bit is enabled vs disabled.


    Regards,

    Aqid


    • Yamada1's avatar
      Yamada1
      Icon for Occasional Contributor rankOccasional Contributor

      Thank you for answering.

      The materials you provided were very helpful.

      thank you.

  • AqidAyman_Altera's avatar
    AqidAyman_Altera
    Icon for Regular Contributor rankRegular Contributor

    I’m glad that your question has been addressed, I now transition this thread to community support. If you have a new question, please login to ‘https://supporttickets.intel.com’, view details of the desire request, and post a feed/response within the next 15 days to allow me to continue to support you.


    It will be appreciated if you can do the service evaluation survey based on my support.