the Quotient is floating point in vhdl

what are the two operands? diving two integers gives you an integer and remainder result (if you use the IP core). If you use correct scaling, you can get a fixed point output. You only get a floating point result if both inputs were floating also.

hi tricky

8/12 = 1 and remainder 4. Not 0.666666. If you use different scaling you can get more accurate results. It will not be floating point unless you convert both 8 and 12 to floating point (32 bit usallly).

thanks tricky a lot for helping my design is used to measure the distance between two input data in the following code i used the accum to sum the distances measurements and the counter to count the numbers of data measured and i want to divide the accumulator result on the counter result .if you understand me well , is this possible or i should use the trigger signal to sense the last sample input . if that i said is wrong ,so i will divide accumulator on the counter result. sorry for ad English and i hope you help me thank a lot. i attache the code and the simulation picture . i want to thank kaz for helping me before to make this code thanks kaz very much

Floating point is most likely not the best solution for your problem, a 8.8 fixed point number sounds like a better idea. You easily get it by multiplying the dividend with 256 before the division.