Help me with this problem

You assume the bits of the code enters synchonoulsy with the fpga code. ok.

I suggest write 2 components:

a-One that turn on a LED when you put '1' on an input. Call it "trigger_a".

b-turn on the third LED when you put '1' on input, called "trigger_b".

This components act like monostables circuits. You can describe in vhdl:

entity mono_led_2 is

port(

clk : in std_logic;

n_clr : in std_logic;

trigger_a : in std_logic;

led_2 : out std_logic

);

end entity mono_led_2;

The other entity is very similar. With a simple state machine and a counter you can do it.

So, in the main code, the architecture "programa", when you reach the proper state to turn on the second LED, simply put '1' on trigger_a, and in the next state, put '0' on trigger_a to avoid retrigger:

when zero =>

trigger_a <= '0';

trigger_b <= '0';

led <= "100";

A(0) <= interrup(7);

nx_state <= one;

when one =>

led <= "100";

A(1) <= interrup(6);

nx_state <= two;

when two =>

led <= "100";

A(2) <= interrup(5);

nx_state <= three;

when three =>

led <= "100";

A(3) <= interrup(3);

nx_state <= four;

when four =>

led <= "100";

if(A = "1111") then nx_state <= five;

else nx_state <= six;

end if;

when five =>

trigger_a <= '1';

led <= "010";

nx_state <=zero;

when six =>

trigger_b <= '1';

led <= "001";

nx_state <=zero;

end case;

You have to instantiate both components.