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Your work-around of 9 bits shift then taking 16 LSBs doesn't make sense to me.
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This does not makes sense to me, too. That's why I'm not happy with this solution.
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To avoid calculation problems of software Let us go back to your simple example:
You said for your input sine of 30146 amplitude you get fft output as:
Real: 3384 (0x0D38)
Imaginary: -14391 (0xC7C9)
fair enough. what is your exponent value in above example?
It should be -1 so that output scales to 2^ -(-1) = 2
otherwise there is something wrong.
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The exponent within this example is -10. Yes, there seems to be something wrong, but what is the question.
Honored Contributor
