text to mif conversion

Hi,

I use the Fixed-Point toolbox that is embedded in Matlab to convert data to hex format. With this you can select rounding modes(ceil, floor, fix, convergent, nearest, round), define overflow behavior (wrap, saturate), word length, fraction length, signedness, and data types (fixed, the built-in single and double). Moreover, you can display your object in the equivalent hex, bin, oct and int of the stored bits. I understood that you can build objects with up to 65536-bit length.

function generate_mif(filename, data, depth, width, frac, sign)
% data is a vector
fid = fopen(filename, 'w+');
fprintf(fid, 'WIDTH=%d;\n', width);
fprintf(fid, 'DEPTH=%d;\n\n', depth);
fprintf(fid, 'ADDRESS_RADIX=UNS;\n'); % UNS, BIN, HEX, ...
fprintf(fid, 'DATA_RADIX=HEX;\n\n');
fprintf(fid, 'CONTENT BEGIN\n');
fi_data = fi(data, sign, width, frac, 'RoundMode', 'nearest');
for i = 1:depth
    fi_temp = fi_data(i);
    fprintf(fid, '\t%-4d:   %s;\n', i-1, fi_temp.hex);
end
fprintf(fid, 'END;\n');
fclose(fid);

Test the function with this code:

filename = 'sin96.mif';
depth = 96;
width = 36;
frac = width-1; % range: [-1,+1)
signed = true;
data = sin(2*pi*0.05*(1:depth));
generate_mif(filename, data, depth, width, frac, signed);
plot(data); grid on;

Explore this toolbox. It's very useful. :)

Hi Zainab,

data is the vector(array) in Matlab that contains your data to be written into named mif file. It is meant to be signed integer (no fractions) in the code (since data radix is made decimal).

if your data is not scaled then the following statement creates signed integers scaled to 10 bits signed:

data = randn(1,2048); %unscaled floating

data = round((2^9-1) * data/max(abs(data)));

in this case your array length is 2048 to replace "k"

i'm sorry,kaz.

again, i try your suggestion.but then, i have this error.

Error in ==> pingu2 at 10

fprintf(fid,'%i : %i;\n',k-1,data(k));

what is 'data' means here?is it the name of file?

thank you.

Hi Zainab

If I understood you you want 16bits width and 4096 depth

fid = fopen('filename.mif','w');

fprintf(fid,'--MIF data generated by MATLAB\n');

fprintf(fid,'--Date: %s \n\n', date);

fprintf(fid,'WIDTH=16;\n');

fprintf(fid,'DEPTH=4096;\n');

fprintf(fid,'ADDRESS_RADIX=UNS;\n');

fprintf(fid,'DATA_RADIX=DEC;\n');

fprintf(fid,'CONTENT BEGIN\n');

for k = 1:4096

fprintf(fid,'%i : %i;\n',k-1,data(k));

end

fprintf(fid,'END;');

fclose(fid);

i have this full program,its work.but then when i want to change the spesific size,it have the error.

-----------------

name = 'image';

img = imread(strcat(name,'.gif'));

g = im2double(img);

g = g/max(max(g));

rgb = cat(3,g,g,g);

imshow(rgb);

out = ones(480,640);

out(10+(1:460),90+(1:460)) = img;

imshow(out);

x = out';

x = uint8(x(:));

n = length(x);

y = reshape(x,8,n/8)';

z = y(:,8);

for i=1:7

z = bitor(z,bitshift(y(:,i),8-i));

end

m = 0;

n = 1;

v = z(1);

for i=2:length(z)

if (z(i)~=v)

m = m + 1;

value(m) = v;

runlen(m) = n;

n = 1;

v = z(i);

else

n = n + 1;

end

end

m = m + 1;

value(m) = v;

runlen(m) = n;

fprintf('total runs %d\n',sum(runlen));

fprintf('number of runs %d\n',length(runlen));

nz = length(find(value==0));

nf = length(find(value==255));

fprintf('zeros %d all ones %d\n',nz,nf);

dfv = 255;

fid = fopen(strcat(name,'.mif'),'w');

str = 'WIDTH=8;\nDEPTH=38400;\n\nADDRESS_RADIX=HEX;\nDATA_RADIX=HEX;\n\n';

fprintf(fid,str);

str = 'CONTENT BEGIN\n [0000..%04X] : %X;\n';

fprintf(fid,str,sum(runlen)-1,dfv);

n = 0;

for k=1:length(runlen)

if (runlen(k)==1)

str = sprintf(' %04X : %X;\n', n, value(k));

else

str = sprintf(' [%04X..%04X] : %X;\n', n, n+runlen(k)-1, value(k));

end

if (value(k) ~= dfv)

fprintf(fid,str);

end

n = n + runlen(k);

end

fprintf(fid,'END;\n');

fclose(fid);

--------------

can you show me how to make the image 16bits width and 4096bits depth.

which part should i alter?

thank you.

Hi,

You better use a program to write the mif files as copy/paste is suitable for small size data.

Here is an example

Using Matlab to write 256 signed data to 16 bit mif:

fid = fopen('filename.mif','w');

fprintf(fid,'--MIF data generated by MATLAB\n');

fprintf(fid,'--Date: %s \n\n', date);

fprintf(fid,'WIDTH=16;\n');

fprintf(fid,'DEPTH=256;\n');

fprintf(fid,'ADDRESS_RADIX=UNS;\n');

fprintf(fid,'DATA_RADIX=DEC;\n');

fprintf(fid,'CONTENT BEGIN\n');

for k = 1:256

fprintf(fid,'%i : %i;\n',k-1,data(k));

end

fprintf(fid,'END;');

fclose(fid);

*****************

I want to find a solution for converting images to .hex / .mif format. Can i change it by using the converter (please suggest to me) or do I need to make their own code by matlab or another software.?

thank you in advance for any help from members..

I assume you use Matlab, here is short cut:

convert your data to signed integers:

data = round(data *(2^15-1)/max(data)); %for 16 bits mif

then display as column:

data'

copy and paste the column to a mif in quartus as follows:

open a new mif with 16 bits width. change data view to signed then copy the data directly, save and enjoy...