Occasional ContributorQuestion about register's initial value
Hello, I have a question about the initial value of registers in verilog. I have heart two kinds of views.
code for example:
//verilog
reg [7:0] test_reg = 8'b1111_0000;
1. the initial value is determined by part and technology, hence no matter what value i set when definite this variable, it will be set all '0' or all '1' when power-up.
2. the value i set when definition is the value when power-up. ( i heart new fpga parts don't suggest use 'if(reset==0)' in always block.)
i can't find the precise answer of this question in search engine, please give me a official answer.
Thank you!
Hi,
You can set the Power-Up Level option for one or more registers. If registers do not have asynchronous load capability on the chosen device, then a register that uses asynchronous clear cannot power up to High. Similarly, if registers do not have asynchronous load capability on the chosen device, then a register that uses asynchronous preset cannot power up to Low. Note that Quartus Prime Integrated Synthesis reads default values for registered signals defined in VHDL code and converts the default values into Power-Up Level settings. The software also synthesizes variables that are assigned values in Verilog HDL initial blocks into power-up conditions.
You may refer to Chapter 1.5.1: Register Power-Up Values for details
Thanks.
Best regards,
KhaiY
