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Altera_Forum's avatar
Altera_Forum
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16 years ago

Problem with verilog

First of all excuse my english (french guy)

Well i want to do something simple with quartus but it doesn't work!

the idea is the following one:

i have a counter "count", 2 clocks "CLK1" and "CLK2" and a button "Bu"

when Bu=0

count=count+1 at each posedge of a clock "CLK1"

when Bu=1

count=count+1 but on posedge of another clock CLK2 more rapid than CLK1

when Bu returns to 0, count increases at the rythme of CLK1

CLK1 pos pos pos

CLK2 pos pos pos pos pos pos pos pos pos pos pos

Bu 000000000000000000000000000011111111111000000000

count 0 1 2 3 4 5 6

Someone can help me?

Thanks

2 Replies

  • Altera_Forum's avatar
    Altera_Forum
    Icon for Honored Contributor rankHonored Contributor
    16 years ago

    Another method would be to use two counters for each clock domain. Then design a module to re sync the counter values to the same clock domain before adding them together to get the total count.

  • Altera_Forum's avatar
    Altera_Forum
    Icon for Honored Contributor rankHonored Contributor
    16 years ago

    Typically it's not possible to use two clocks on a register.

    You should solve it like this:

    always(clk) begin

    if (bu==0) begin

    count <= count + 1'd1;

    end else begin

    count <= count + 5'd20;

    end

    end