Minimum pulse width error

Your voltage to your device is e.g.

1) 3.3V to +ve pin and gnd(0V) to -ve pin, creating 3.3V potential difference or

2) 2.6V to +ve pin and -0.7V to -ve pin, creating 3.3v potential difference too.

Case 1) Your will need go to datasheet single supply which is 100Mhz, whenever your -ve is ground, it is known as single supply

2) You get 310Mhz for putting 1.65V and -1.65V(potential diff 3.3V), meanwhile getting less and less Mhz>>e.g. 2V and -1.3V(potential diff also 3.3V) but get 240Mhz for example. Dual supply method whenever not grounding the -ve pin

It work like swinging voltage, and you can read about the working principle of swinging voltage.

Also, changing the 2mA means you are doing current source, LED is sourcing current because forward voltage of LED=Vf from fundamentals of LED is a fixed voltage at the PN junction. Whereas for motors/processors, you are only playing with the voltage, means source voltage, changing voltage at +ve and -ve there you will get difference ranging Mhz as I explain on top. This is how datasheet have min value, typical value, and maximum value.

I assume you are grounding your -ve pin, which is 0V, and so the minimum is 10Mhz at mode x1.