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Mateusz1's avatar
Mateusz1
Icon for New Contributor rankNew Contributor
3 years ago
Solved

Device speed grade

Hello

Is there a way to check device speed grade from software?
For example something like "Chip ID Intel IP". I cant check speed grade from device package.
Can i get it in some way from device registers (if its there)?

  • Nope, not available. The JTAG ID encodes the specific device family and size (number of cells), and number of I/Os (package type, sometimes). Speed grade and temperature grade are not encoded. They are determined after the die is packaged and tested.

    You could do that yourself if you wanted to add specific registers for your application that encode such info, but it will not be available on unprogrammed parts direct from the factory.

4 Replies

  • ak6dn's avatar
    ak6dn
    Icon for Regular Contributor rankRegular Contributor

    Nope, not available. The JTAG ID encodes the specific device family and size (number of cells), and number of I/Os (package type, sometimes). Speed grade and temperature grade are not encoded. They are determined after the die is packaged and tested.

    You could do that yourself if you wanted to add specific registers for your application that encode such info, but it will not be available on unprogrammed parts direct from the factory.

  • AqidAyman_Altera's avatar
    AqidAyman_Altera
    Icon for Regular Contributor rankRegular Contributor

    Hi Mateusz,


    Alternative solution, I would recommend you to check on the device overview document for specific family device. From there, you can see the speed grade for the device based on the Device Packaging Ordering Information.



  • AqidAyman_Altera's avatar
    AqidAyman_Altera
    Icon for Regular Contributor rankRegular Contributor

    Hi,

    I’m glad that your question has been addressed, I now transition this thread to community support. If you have a new question, feel free to open a new thread to get support from Intel experts. Otherwise, the community users will continue to help you on this thread.

    Thank you.