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Honored Contributor
10 years agoi figure out these questions:
1. in the digital binary system, the 5120*32bit occupy the same resourses as 9182*32bit. so in order to use the M9K more efficiently, i should change the On-Chip Ram size from 5120*32 to 4096*32. i test this method on my project, and i works. 2. the "jtag_uart_0_scfifo_r" and the "jtag_uart_0_scfifo_w" only have 512 bits, but each of them occupy 1 M9k, so i enlarge the JTAG UART fifo buffer depth from 64 to 1152, so the system gets more JTAG UART fifo buffer depth without cost more M9ks.