Forum Discussion
Altera_Forum
Honored Contributor
15 years agoThis gives as output:
Transfer size: 0x10
Content of TX DDR2 SDRAM after DMA operation
Address 0xC000000: 1
Address 0xC000004: 2
Address 0xC000008: 3
Address 0xC00000C: 4
Address 0xC000010: 5
Address 0xC000014: 6
Address 0xC000018: 7
Address 0xC00001C: 8
Content of RX DDR2 SDRAM after DMA operation
Address 0xD500004: 1
Address 0xD500008: 2
Address 0xD50000C: 3
Address 0xD500010: 4
Address 0xD500014: 540006
Address 0xD500018: 540007
Address 0xD50001C: 540008
Address 0xD500020: 540009
Memory compare from starting addresses 0xC000000 and 0xD500004
with 0x10 bytes gives 0x0
Transfer size: 0x10
Content of TX DDR2 SDRAM after DMA operation
Address 0xD500004: 1
Address 0xD500008: 2
Address 0xD50000C: 3
Address 0xD500010: 4
Address 0xD500014: 540006
Address 0xD500018: 540007
Address 0xD50001C: 540008
Address 0xD500020: 540009
Content of RX DDR2 SDRAM after DMA operation
Address 0xF000004: 540001
Address 0xF000008: 3
Address 0xF00000C: 2
Address 0xF000010: 540006
Address 0xF000014: 0
Address 0xF000018: 0
Address 0xF00001C: 0
Address 0xF000020: 0
Memory compare from starting addresses 0xD500004 and 0xF000004
with 0x10 bytes gives 0xFFFFFFAC
The 540006 etc. is old data that I didn't clear yet. Clearing it with the following function, makes those values 0. memset((void*)memory_base,0x00, memory_size); //Clear memory