Forum Discussion
AZeli
New Contributor
7 years agoThank you for the response.
I connected a USB blaster to J2 and scanned the chain. I see two devices - the FPGA and a virtual device. I didn't see the CPLD on the chain, which led me to suspect that there is a separate JTAG chain for it. I think I also figured out the EPCQ already.
Is there a way to eliminate the virtual device from the chain?
AnandRaj_S_Intel
Regular Contributor
7 years agoHi AZeli,
Yes, can eliminate the virtual device from the chain using DIP switch SW1.
SW1.4 Logic 0 = Vitual JTAG Bypass
Logic 1 = Vitual JTAG Enable
Regards
Anand