Forum Discussion
1 Reply
- Altera_Forum
Honored Contributor
You should see it by looking at the source code. If I remember right# , & and $ are OR, AND, XOR.
Howdy, im trying to covert some code, and looking at the equation files i'm getting results like this:
B1L1 = (SW[2] & (((SW[3])# (!SW[1]))# (!SW[0])))# (!SW[2] & ((SW[1] $ (SW[3])))); What does the# operator, $ operator stand for? Thanks! I'm in a little bit of a time crunchYou should see it by looking at the source code. If I remember right# , & and $ are OR, AND, XOR.