Dividing array in parts.

you cannot do that with a 2d array, you can only access one entry at a time.

for this, you would need a loop (ps. I think you means to assign output, not input!)

for i in input'range(1) loop
  for j in input'range(2) loop
    output(i,j) <= input(i,j);
  end loop;
end loop;

Thanks Tricky. You are always saving my life.

As soon as possible I will teste and reply.

Thanks again!

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you cannot do that with a 2d array, you can only access one entry at a time.

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Respectively a row slice at once. Keep in mind, that a 2D array isn't but a mapping scheme to represent data structures, that are 1D arrays by nature.

It didn't worked, I get an error:

"indexed name returns a value whose type does not match "array_t", the type of the target expression."

Type array_t IS ARRAY (0 to 7, 0 to 7) OF STD_LOGIC_VECTOR(0 to 7);

Type array_t2 IS ARRAY (0 to 511, 0 to 511) OF STD_LOGIC_VECTOR(0 to 7);

SIGNAL output: array_t

SIGNAL input: array_t2

process(clk)

begin

for i in 0 to 7 loop

for j in 0 to 7 loop

output<=input(i, j);

end loop;

end loop;

end process;

Thank You!

you need to change it to

output(i, j) <= input(i,j);

Oh...Ok,

Thanks!

The code worked fine if I want to do something using the same index:

output(0, 0) <= input(0, 0);

but how about

output(0, 0) <= input(8, 8);

output(0, 1) <= input(8, 9);

How can be done that?

Thank You!

I have tried this before and didn't worked. But the error was somewhere else.

This works.

output(i, j) <= input(i, j+8);