Anonymous
5 years agoConfused in logic!
Hi Helpers!
I am working on a project in which i have to create 8:1 mux using 4:1 mux, I am done with the 4:1 code and then create symbol file which i used for making 8:1 mux .
4:1 code is mentio...
Without seeing the testbench or the waveform, it's hard to figure out what's wrong here.
If A[2] is the enable signal, I'm not sure why you are inverting it going into the upper mux.
And your s0 line (D[2]) is disconnected from the upper mux in the schematic.
I am New to this coding area!
PLEASE help me clear my basics!
Suppose i have a 4:1 mux and have 4bit input i0,i1,i2,i3, (s0,s1)select lines and output Y.
I use two vcc pins A and B to connect with 4:1.
I want to know that when WE USE RTL Simulation It Give random values to the input and check expected output with the current output , It give random value to A and B or i0,i1,i2,i3.
Can anyone help me design or can anyone design 8:1 mux using 4:1 mux?
If you want to design 8:1 mux using 4:1 mux, perhaps the link below may helps.
Let me know if you need further help with this circuit design.
https://www.tutorialspoint.com/digital_circuits/digital_circuits_multiplexers.htm
@RichardTanSY_Altera I want to build 8:! mux using only 4:1 mux and i tried everything but always error occur:(