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Honored Contributor
Honored Contributorhow to calculate the number of M9k that nios onchip memory occupied?
hi everyone in project A, i set the nios onchip memory size to be 20480 bytes, the quartus told me(Fitter report) it occupy 20 M9Ks, its implementation bits is 163840 then i use copy project...
Altera_ForumHonored Contributor
Honored Contributor --- Quote Start --- why in project A it only occupy 20 M9Ks? --- Quote End --- This is fine and makes perfect sense. 1024 bytes per M9K block. 20 x 1024 bytes = 20 M9K blocks. --- Quote Start --- why in project B it occupy 32 M9Ks? --- Quote End --- It shouldn't. I can only presume you are not (quite) doing what you think you are in copying the project. --- Quote Start --- i am a little confused, in binary system, the 20480 bytes should occupy the same space with 2048*16 bytes, that is 2048*16*8=83,886,080bits=28.4 M9Ks, that is 29M9Ks --- Quote End --- I dare say you are 'a little confused'. 20480 bytes fits into 20 x M9K blocks, as project A confirms. 28.4, 29 or 32 are not necessary. I suggest you do a little more digging. Cheers, Alex
