signed/unsigned multipliers

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let us assume the numbers are signed:

111 * 011 (as signed I expect the result to be -1 * 3 = -3

now sign extend according to tricky's trick:

111 111 * 000 011

the verdict:

= 10111101

and means -128 + 61 and /= the expected -3

So what is going on Now?

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you're forgetting that the result is only 6 bits because you had 2 x3 bit inputs. you ignore bits 6 and 7 (only bits 0-5 are valid)