Honored ContributorHi,
in the datasheet of the MAX10 FPGA type10M50DAF484C8GES I read that the on-chip memory has a size of 1,677,312 kbits. This means a size of more than 209 MBye. This seems to be extremely large. Is this correct? Second question: I want to devide this on-chip memory into 24 FIFOs of 2 MByte, 12 bit wide. Can I do this? Thank you. Regards.
Honored ContributorFor a 10M50 my datasheet says M9K memory (Kb = Kbytes?) is 1638. I take this as 1638 x 1024 =1677312 bits. So ... 1677312/1024= ~1638 KBytes ~= 1.6 MB.
Honored ContributorMAx 10 never own such huge capacity of memory for that cost... else the cyclone V and Arria 10 can retire already...
Honored Contributorand max 10 implementation need to be careful as you can easily used up those spaces.
Honored ContributorBMW
it is in bits not kbits so: 1,677,312 bits == 205KBytes of memory.Honored Contributor
