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10 years agoFor a 10M50 my datasheet says M9K memory (Kb = Kbytes?) is 1638. I take this as 1638 x 1024 =1677312 bits. So ... 1677312/1024= ~1638 KBytes ~= 1.6 MB.
For a 10M50 my datasheet says M9K memory (Kb = Kbytes?) is 1638. I take this as 1638 x 1024 =1677312 bits. So ... 1677312/1024= ~1638 KBytes ~= 1.6 MB.