Forum Discussion
Altera_Forum
Honored Contributor
11 years agoYou only have indirect control over the end address. The way it works is you expose slave address bits which Qsys uses to determine the span the slave port takes up in the memory map. When you enter the slave ports base address the end address moves with it so you don't have direct control over that field. The end address = <base address> + <slave span> - 1. I didn't realize your components were a single 8-bit location so that's why the start and end address is the same (span is 1 which cancels out the -1 in that calculation).