demodulator with altera megafunction

--- Quote Start ---

how did you find n and Wn of FIR1 matlab function?

Thanks

--- Quote End ---

cut off = 10Hz on a sampling frequency of 1KHz i.e. cutoff is 10/1000 relative to Fs of 1(1 cycle or 2pi)

hence 10/1000 *2(pi) = 20/1000 pi = .02 pi

n is experimental to get -60dB, you can use other options...

apply freqz to see:

freqz(h,1,0:.01:500,1000);