Forum Discussion
Altera_Forum
Honored Contributor
7 years ago --- Quote Start --- FPGA synthesis never implements any resource that isn't "actually used". I guess the problem is that you don't understand which part of the code infers a RAM based shift register. But without seeing the code, it's hard to tell. The hierarchy view already tells you that it's used in the implementation of dataodd_rtl. There's no additional autogenerated logic, it's just the way how altshift_taps is implemented. --- Quote End --- I used data odd here : BEGIN IF (rising_edge (clk)) THEN Splitter<=Original(generaladdress); dataeven <= Splitter(9 downto 0); dataodd<=Splitter(19 downto 10); if kk=2 then First_Reg<=dataeven; else evenbuff<= dataeven; end if; xoddbuff<=dataodd; oddbuff<=xoddbuff; It temporary holding a value since I need to wait for one clock cycle, however, I defined it as signal of unsigned, I don't know why it used as m4k?