Forum Discussion
fxu001
Occasional Contributor
7 years agotiming in I/O pads
Hello, Currently, I passed all setup, hold, recovery and removal timing within the FPGA with constraint all paths and I/Os, but my I/O through GPIO portion did not passed the timing. Do you have any...
KhaiChein_Y_Intel
Regular Contributor
7 years agoHi fxu001,
For LOC equivalent assignment , you may refer to https://www.intel.com/content/dam/www/programmable/us/en/pdfs/literature/an/an307.pdf ( Chapter 4.3.2 Table 57)
Thanks.
- fxu0017 years ago
Occasional Contributor
Hi YY, Great info. Next step is how to open the floorplan editor which it is equivalent Xilinx tool, so I can check the location and lock them; then, I check the timing. BTW, I solve the timing different in the different I/O banks; basically I evenly distribute AV bus during feed into JESD204B IP. I am close to reach timing in the I/O pads, but I still need to understand Altera tool. Internal timings are okay. Thanks, -Fred - fxu0017 years ago
Occasional Contributor
Hi YY, BTW, can you help me to ask JESD204B designer what 8B/10B protocol does he/she use in the RTL since I cannot figure out the output pattern because RTL in that portion is encrypted? I can find out 10B in the serial bus based on tx_link_clk_clk clock cycle, but no matter how to shift location, and I cannot find the pattern matches Wikipedia 8b/10b encoding. Maybe he/she jump to use. Since I cannot access IEEE JESD204B std, is it possible to give me some hint? He/she can give me the example during input is 0 (zero) in the JESD204B AV bus and what do expect value output in serial bus. From I analyze your JESD RTL and waveform, I think what he/she design way is feed 64 bus through JESD204B AV bus; then, the logic split up and low 32 bits bus. After that, the serial bus will first send out low 32bits through 8b/10B and converted to 40bits. From the RTL, he/she uses the little endian tech. I also file the case for 8b/10b issue. Thanks, -Fred - fxu0017 years ago
Occasional Contributor
Hi YY, Don’t bother about 8B/10B issue since I found solution from EEtimes which it started K28.5 parameters with RD=-1 and RD=+1 with repeat pattern. Thanks, -Fred