Forum Discussion
Altera_Forum
Honored Contributor
17 years agoHi POWERGUI
To sum up, I hope the following method will work: (we only need saturation if there is feedback. If there is no feedback then we can accommodate the result). Assume adder inputs are x1, x2 each 8 bits 2's complement and adder result is S of 9 bits. for feedback x2 = S(8) & S(6:0). i.e. discard S(7). This brings us back to the concept of MSB discarding algorithm, thus: if S(7) is opposite S(8) then fill up all S(or x2) with opposite of S(8).