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Altera_Forum
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13 years ago

Quartus eliminates intermediate signal causing an overflow.

I have the following code: input signed b; input signed c; input signed d; output signed e; wire signed f; assign f = b*c/d; assign e = f I believe that Quartus is eliminating f and rep...
Altera_Forum's avatar
Altera_Forum
Icon for Honored Contributor rankHonored Contributor
13 years ago

You didn't need to use the keep keyword for this to work right? (I wouldn't expect you to really need it if you break the calcuation down into two assign statements with the appropriate widths).

I recommend not getting into a habit of using the keep keyword since it prevents having Quartus II optimizing that net when it or portions of it are not used in your design. I normally only use it for debug purposes.