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If the compiler doesn't know how many times the loop is going to iterate then I wouldn't expect it to unroll the loop for you. So by not specifying an initial value for 'idx' the compiler has no clue if it should unroll the loop 2, 3, 4, 5, ...100, etc.... times. Loop unrolling is a static optimization so all the unknowns need to be.... known for the optimization to occur.
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Thanks for answer :)
But,
int main()
{
UINT32 idx;
while(idx>7)
{
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
*((volatile UINT32* )(0x00000000)) = 0;
idx-=8;
}
while(idx!=0)
{
*((volatile UINT32* )(0x00000000)) = 0;
idx--;
}
while (1);
return 0;
}
That a way to unrool dynamic loop no ?
The compilateur is afraid by that ?
or i don't have understood your answer ?
Honored Contributor
