vhdl -division program

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but 1/b also has a division then how can it accept?. or how to do it

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you can look at 'a' as an 8 bit integer, say 51 which is 00110011

say you wanted to divide by 3. we will actually multiply by 1/3 in 8 bits fractional, so 'b' is 0.010101

00110011 x 0.010101 = 000010001.0000100

51 * 0.328125 = 17.03125

the decimal point is an abstraction. anyhow, this may work for your application (maybe if 'b' only has a few possible values) and only uses a 9 bit signed multiplier. hopefully someone can double check my work, its been awhile...