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You can easily see, that it's impossible to achieve a several 100 MHz resonance above a certain coil inductance. But there's no need to have more than one turn with your coil, thus you may be still able to design a coupler with sufficient output level.
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Could you please elaborate more on this?
I understood what you said, still I do not understand the reason or the explanation of it.
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You should consider however, that you're effectively operating a RF transmitter with considerable output power (mW range)
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What is the best way to measure transmitted power in this case? Isnt the average power consumed by the coil is zero?
I know if I want to transmit more voltage, I have to transmit less current. But since I am dealing with FPGA, I am more interested to transmit higher voltage. How would I increase the transmitted power?
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and that your instrument won't pass EMC tests unless the coupler is completely shielded by a metallic enclosure. Even if you would use a free ISM (industry, science and medical) frequency, the clock signal has to be thoroughly filtered from harmonics.
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okay give me a moment here.
1. I have to make an EMC test?
2. How should I filter my transmitted signal? Just use a bandpass digital filter at the output of FPGA1 (the transmitter)? or programming this FPGA to do that job and output a filtered signal is a better option?
3. Will it really cause me, as a person, a problem to send a wireless signal with some harmonics outside the ISM band?
Thanx! Interesting discussion we have here!
Honored Contributor
