How to request multiply MSI interrupts?

Ok for the advice!

Now

I finally implemented my first MSI Interrupt.

But

1 ) why I can not get pci-msi-edge on my device after the linux command:cat /proc/interrupts while it looks good with the command lspci -d 1204:ec30 -v -xxx ( see the 2 outputs below)

2) I permanently get an error by implementing pci_enable_msi_block (struct pci_dev * dev, unsigned int nvec) where can I get the related patch for arch x86?

# lspci -d 1204:ec30 -v -xxx
04:00.0 Non-VGA unclassified device: Lattice Semiconductor Corporation Device ec30
        Subsystem: Lattice Semiconductor Corporation Device 3030
        Physical Slot: 3
        Flags: bus master, fast devsel, latency 0, IRQ 30
        Memory at d0440000 (32-bit, non-prefetchable) 
        Memory at d0400000 (32-bit, non-prefetchable) 
        Capabilities:  Power Management version 3
        Capabilities:  MSI: Enable+ Count=1/1 Maskable- 64bit+
        Capabilities:  Express Endpoint, MSI 00
        Capabilities:  Device Serial Number 00-00-00-00-00-00-00-00
00: 04 12 30 ec 07 04 10 00 00 00 00 00 10 00 00 00
10: 00 00 44 d0 00 00 40 d0 00 00 00 00 00 00 00 00
20: 00 00 00 00 00 00 00 00 00 00 00 00 04 12 30 30
30: 00 00 00 00 50 00 00 00 00 00 00 00 07 01 00 00
40: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
50: 01 70 03 00 00 00 00 00 00 00 00 00 00 00 00 00
60: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
70: 05 90 81 00 0c 10 e0 fe 00 00 00 00 a9 41 00 00
80: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
90: 10 00 01 00 00 80 00 00 00 00 00 00 11 74 00 00
a0: 00 00 11 00 00 00 00 00 00 00 00 00 00 00 00 00
b0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
c0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
d0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
e0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
f0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
# cat /proc/interrupts
            CPU0
   0:     116261   IO-APIC-edge      timer
   1:          2   IO-APIC-edge      i8042
   3:          2   IO-APIC-edge
   4:          2   IO-APIC-edge
   5:          0   IO-APIC-edge      parport0
   7:          0   IO-APIC-edge      LATTICE_pci
   8:          1   IO-APIC-edge      rtc0
   9:          0   IO-APIC-fasteoi   acpi
  12:          4   IO-APIC-edge      i8042
  16:      79998   IO-APIC-fasteoi   pciehp, pciehp, pciehp, pciehp, ehci_hcd:usb2, ohci_hcd:usb6, ohci_hcd:usb7, ohci_hcd:usb8, HDA Intel
  18:          0   IO-APIC-fasteoi   mmc0, mmc1
  19:      13861   IO-APIC-fasteoi   ehci_hcd:usb1, ohci_hcd:usb3, ohci_hcd:usb4, ohci_hcd:usb5
  24:          0   PCI-MSI-edge      aerdrv
  25:          2   PCI-MSI-edge      aerdrv, pciehp

--- Quote Start ---

Yes.

If you have a single MSI vector, you have to register 1 interrupt line.

If you want to test CAN, UART interrupts, than write your kernel module.

Request irq for CAN, than for UART, with interrupt handlers.

For ex:

static irqreturn_t can_isr ( int irq, void *dev )

{

void testCAN();

printk(KERN_DEBUG " CAN received irq = %d \n", irq);

return IRQ_HANDLED;

}

static irqreturn_t uart_isr ( int irq, void *dev )

{

void testUART();

printk(KERN_DEBUG " UART received irq = %d \n", irq);

return IRQ_HANDLED;

}

--- Quote End ---