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Altera_Forum
Honored Contributor
12 years agoi should clearify some things .
we will made mem1(consist of addresses for every data input ) i.e address from 1,2,3,4.... to end of the mem1 data input,ok mem2 (consist of addresses for every data input ) i.e address from 1,2,3,4.... t0 end of the mem2 data input,ok check if any of the data input from mem1 = any data input from mem2 . i.e the position of each element in mem1 and the position of the same element in mem2 so the address to the same element will be different in the two mem the address difference will be the distance measure. thanks kaz ,i hope we finish this and help some others pepole at the same domine