Forum Discussion
Altera_Forum
Honored Contributor
15 years agoit wont be as simple as 43 adders
if x is 8 bits, x^2 will need 16 bits, and x^3 needs 24. Then if A,B,C,D are 8 bits again, the output is going to be 32 bits. So thats a lot of adders. Different devices have different size LEs - some have 4input LUTs, some have 6. So to estimate the number of LEs required its simpler just to write the code and compile it.