Forum Discussion
tehjingy_Altera
Regular Contributor
3 years agoHI Alex
Could you try the GIC number 75?
From your design in previous case. Your interrupt is connected to f2h_iirq0 number 3.
From the GIC table, it should be 75.
Regards
Jingyang, Teh
CAlex
Contributor
3 years agoHi,
when I use 75 as the number in my kernel module,
the insmod failed
insmod: ERROR: could not insert module p3.ko: Invalid parameters
duel to request_irq()
Reguards.