perfomance counter clock cycle?.

Hi,

this is my C code:

# include <stdio.h>

# include "alt_types.h"

# include "system.h"

# include "altera_avalon_performance_counter.h"

int main()

{

PERF_RESET(PERFORMANCE_COUNTER_BASE);

PERF_START_MEASURING(PERFORMANCE_COUNTER_BASE);

PERF_BEGIN(PERFORMANCE_COUNTER_BASE, 1);

int x,y,z;

x=10;

y=10;

z=x+y;

PERF_END(PERFORMANCE_COUNTER_BASE, 1);

PERF_STOP_MEASURING(PERFORMANCE_COUNTER_BASE);

perf_print_formatted_report((void*)PERFORMANCE_COUNTER_BASE, ALT_CPU_FREQ,2, "total","time" );

// printf("value of c %d\n",c);

return 0;

}

I get the following output: from console:

nios2-terminal: connected to hardware target using JTAG UART on cable

nios2-terminal: "USB-Blaster [USB-0]", device 1, instance 0

nios2-terminal: (Use the IDE stop button or Ctrl-C to terminate)

--Performance Counter Report--

Total Time: 8.98E-06 seconds (449 clock-cycles)

+---------------+-----+-----------+---------------+-----------+

| Section | % | Time (sec)| Time (clocks)|Occurrences|

+---------------+-----+-----------+---------------+-----------+

|total | 72.4| 0.00001| 325| 1|

+---------------+-----+-----------+---------------+-----------+

|time | 0| 0.00000| 0| 0|

+---------------+-----+-----------+---------------+-----------+

Is the total clock cycles shown correct; because for just addition operation , does the Nios II take these many clock cycles?.

anyone pls help me whether I'm doing the right thing.

Thanks,

Anand