Forum Discussion
There's no need to do this. Just enable a second PLL output and use it as a pass-through, matching the properties of the input clock.
Thank you Sstrell .
Please, can you give me a example shematic or where can i find an example ?
One source (4 or 8 mhz ) will be connected to around 40 or more receiving functions.
The other clocks will be connected to about 20 receiver functions.
- sstrell5 years ago
Super Contributor
I'm not sure I understand what you're saying. But what I'm saying is to go into the IP Parameter Editor for the PLL and enable additional clock outputs there. So you'd have the c0 like you have in the schematic but also a c1, which can be independently configured.
- fgh39825 years ago
New Contributor
Thank you.
Apart from the clk0 leg of the FPGA , my design is in the FPGA .
I try this example, but it does not work .
I did not draw the functions that receive the clocks .
Are there functions "like buffers" in Quartus to multiply the same signals ?
Thanks again in advance .
Regard .
- sstrell5 years ago
Super Contributor
Why are you adding additional clock dividers on the outputs of the PLL? Just set the output clocks of the PLL to what you want in the parameter settings for the PLL and then connect those outputs to your logic.
When you say "it does not work", what does that mean? What happens? Errors?