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Altera_Forum
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15 years ago

lpm_divide remainder result

My thread is mainly on the remainder output from the lpm_divide. I am using the lpm_divide megafunction for diving two 16 bit fixed point numbers and the denominator is always greater than or ...
Altera_Forum's avatar
Altera_Forum
Icon for Honored Contributor rankHonored Contributor
15 years ago

That's correct you should get that value as the remainder. As a result I would prescale the numerator more than the denominator so that you get a quotient that is beyond 0 or 1 (otherwise you don't really need a divider to figure out the answer....)