Forum Discussion
Altera_Forum
Honored Contributor
16 years agoHi Kaz,
Thanks for your detailed explanation. I realised that since I have signed numbers(2's complement), and hence no need to convert to unsigned. Cheers BPRHi Kaz,
Thanks for your detailed explanation. I realised that since I have signed numbers(2's complement), and hence no need to convert to unsigned. Cheers BPR