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zasas's avatar
zasas
Icon for New Contributor rankNew Contributor
7 years ago

(VHDL) Help...I set the timer counter code. I want to reset the circuit by pressing it more than 2 seconds. How do I write code?

USE ieee.std_logic_unsigned.all; USE ieee.std_logic_unsigned.all; USE ieee.std_logic_unsigned.all; ENTITY TIMER1 IS digit1, digit2, digit3, clk_period: OUT STD_LOGIC_VECTOR(7 DOWNTO...
AnandRaj_S_Intel's avatar
AnandRaj_S_Intel
Icon for Regular Contributor rankRegular Contributor
7 years ago

Hi @zasas​

Okay, You have to build a counter which will count to 25 million to get 2 second events which will be used for reset.

You can refer below example and use it in you design.

Please note that I have not checked your code.

PROCESS (Clock)
BEGIN
IF (Clock'EVENT AND Clock = '1') THEN
    counter <= counter + '1';
    if( counter = <NUMBER>) then --<NUMBER> =How many clocks will you need to get two second? Well it will be clearly 25 million cycles assusing clock of 50MHz.
        reset<= '1';
        counter <= "0";
    else
        reset<= '0';
    end if;
END IF;
END PROCESS;

Let me know if this has helped resolve the issue you are facing or if you need any further assistance.

Regards

Anand