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KarelSterckx's avatar
KarelSterckx
Icon for Occasional Contributor rankOccasional Contributor
3 years ago
Solved

Syntax error in initial block

I am using Quartus Prime Lite Edition v22.1.1 In my Verilog HDL code, I include the following initial block: initial begin div = 4’b0; lpc = 4’b0; pa = 4’b0; plc_lsb = 8’b0; plc_usb = 8’b0; ...
  • KarelSterckx's avatar
    KarelSterckx
    3 years ago

    Thanks a lot. That is indeed the problem. I have no idea how that back tick crept in as I do not have it on my keyboard. Perhaps I copied it from somewhere though I cannot remember.

_AK6DN_'s avatar
_AK6DN_
Icon for Frequent Contributor rankFrequent Contributor
3 years ago

Ok, I think I found the problem.

I copied your code via cut/paste and it barfs when I compile.

It appears in your constants in the initial block you used a unicode apostrophe character instead of a single ascii apostrophe (').

At least that is what I got when I did a cut/paste of your code verbatim.

Once I went in and edited the constants to use a single ascii apostrophe (ie, like 4'b0) it compiled Ok.

foo.c is your code. The apostrophe character in the constants is '342 200 231' instead of the single ascii apostrophe (') in the edited code bar.c.

par[533] od -c foo.v
0000000   i   n   i   t   i   a   l       b   e   g   i   n  \r  \n   d
0000020   i   v       =       4 342 200 231   b   0   ;  \r  \n   l   p
0000040   c       =       4 342 200 231   b   0   ;  \r  \n   p   a
0000060   =       4 342 200 231   b   0   ;  \r  \n   p   l   c   _   l
0000100   s   b       =       8 342 200 231   b   0   ;  \r  \n   p   l
0000120   c   _   u   s   b       =       8 342 200 231   b   0   ;  \r
0000140  \n   d   s   b       =       9 342 200 231   b   0   ;  \r  \n
0000160   e   n   d  \r  \n
0000165
par[536]
par[536] od -c bar.v
0000000   i   n   i   t   i   a   l       b   e   g   i   n  \r  \n   d
0000020   i   v       =       4   '   b   0   ;  \r  \n   l   p   c
0000040   =       4   '   b   0   ;  \r  \n   p   a       =       4   '
0000060   b   0   ;  \r  \n   p   l   c   _   l   s   b       =       8
0000100   '   b   0   ;  \r  \n   p   l   c   _   u   s   b       =
0000120   8   '   b   0   ;  \r  \n   d   s   b       =       9   '   b
0000140   0   ;  \r  \n   e   n   d  \r  \n
  • KarelSterckx's avatar
    KarelSterckx
    Icon for Occasional Contributor rankOccasional Contributor
    3 years ago

    Thanks a lot. That is indeed the problem. I have no idea how that back tick crept in as I do not have it on my keyboard. Perhaps I copied it from somewhere though I cannot remember.